Simple Harmonic Motion

Modelling oscillations with a = −ω²x and the mass–spring period.

  • Define and explain Simple Harmonic Motion in your own words
  • Use key terms such as simple harmonic motion accurately
  • Apply what you have learned to new examples and questions
  • Avoid the common mistakes learners make with this topic

This lesson focuses on Simple Harmonic Motion: modelling oscillations with a = −ω²x and the mass–spring period.

Definition: Simple Harmonic Motion

Modelling oscillations with a = −ω²x and the mass–spring period.

Key ideas

SHM describes smooth back-and-forth oscillation

In simple harmonic motion the restoring force grows with displacement: a = −ω²x, the minus sign showing acceleration always points back to equilibrium. A mass on a spring has period T = 2π√(m/k); a pendulum has T = 2π√(l/g). Maximum speed occurs at the centre of the swing, maximum acceleration at the extremes.

Circular motion needs a constant centre-seeking force

An object circling at steady speed is accelerating because its velocity direction keeps changing. The centripetal acceleration is v²/r towards the centre, so the required force is F = mv²/r. Remove the force — cut the string — and the object flies off along a tangent, which is why mud flings off a spinning wheel.

Key term — simple harmonic motion: Oscillation where acceleration is proportional to displacement and always towards equilibrium: a = −ω²x.

Worked example: Simple Harmonic Motion

A 0.2 kg mass on a spring (k = 80 N/m) oscillates. Calculate the period.

√(0.2 ÷ 80) = √0.0025 = 0.05, so T = 2π × 0.05 ≈ 0.31 s.

Answer: √(0.2 ÷ 80) = √0.0025 = 0.05, so T = 2π × 0.05 ≈ 0.31 s.

Common mistakes
  • Using T = 2π√(m/k) for a pendulum That formula is for a mass on a spring; a pendulum uses T = 2π√(l/g).
  • Inventing an outward 'centrifugal force' In an inertial frame there is only the inward centripetal force — the outward feeling is just inertia resisting the turn.

Practice

A 1200 kg car rounds a bend of radius 50 m at 20 m/s. Find the centripetal force.
F = mv²/r.

(1200 × 400) ÷ 50 = 480,000 ÷ 50 = 9600 N.

A 0.5 kg ball moving at 6 m/s is stopped in 0.2 s. Find the average force.
Impulse = change in momentum.

Δp = 0.5 × 6 = 3 kg m/s; F = 3 ÷ 0.2 = 15 N.

Two trolleys (2 kg at 3 m/s, 1 kg stationary) stick together after colliding. Find their combined speed.
Conserve total momentum.

Before: 2 × 3 = 6 kg m/s. After: 3 kg × v = 6, so v = 2 m/s.

Why do airbags reduce injury in a crash?
Think about F = Δp/Δt.

They increase the time over which momentum changes, so the average force on the passenger is smaller.

Quick check

Simple Harmonic Motion — quick check

Which of these best defines "simple harmonic motion"?

Oscillation where acceleration is proportional to displacement and always towards equilibrium: a = −ω²x.

In SHM, where are speed and acceleration greatest?

Speed is greatest at equilibrium (maximum kinetic energy); acceleration is greatest at maximum displacement (maximum restoring force).
Key takeaways
  • Simple Harmonic Motion: modelling oscillations with a = −ω²x and the mass–spring period.
  • SHM describes smooth back-and-forth oscillation: In simple harmonic motion the restoring force grows with displacement: a = −ω²x, the minus sign showing acceleration always points back to equilibrium.
  • momentum: Mass × velocity (p = mv), a vector quantity measured in kg m/s.
  • Watch out for: using T = 2π√(m/k) for a pendulum