- Recognise quadratic equations
- Solve quadratics by factorising
- Use the quadratic formula
- Interpret the two solutions
When x is squared
A quadratic equation contains x² (but no higher powers). Its graph is a curve — a parabola — which is why quadratics can have two solutions: the curve can cross the x-axis twice.
A quadratic equation is an equation where the highest power of the unknown is 2,
e.g. x² + 5x + 6 = 0 or 2x² − 8 = 0.
Solving by factorising
The key trick: if two things multiply to zero, one of them is zero. So:
- Rearrange into the form
... = 0. - Factorise the quadratic.
- Set each bracket to zero and solve.
Solve x² + 5x + 6 = 0.
x² + 5x + 6 = 0 (x + 2)(x + 3) = 0 factorise: which pair sums to 5 and multiplies to 6? x + 2 = 0 or x + 3 = 0 x = −2 or x = −3
Check x = −2: 4 − 10 + 6 = 0 ✓
To factorise x² + bx + c, find two numbers that multiply to c and add to b. For x² + 5x + 6: 2 and 3 (2 × 3 = 6, 2 + 3 = 5).
The quadratic formula
Not every quadratic factorises neatly. The quadratic formula solves any quadratic ax² + bx + c = 0:
x = (−b ± √(b² − 4ac)) / 2a
Solve 2x² + 5x − 3 = 0, where a = 2, b = 5, c = −3.
x = (−5 ± √(25 − 4(2)(−3))) / 4 x = (−5 ± √(25 + 24)) / 4 x = (−5 ± 7) / 4 x = 0.5 or x = −3
The part under the square root, b² − 4ac, is called the discriminant.
If it's positive there are two solutions; if zero, one repeated solution; if negative, no real solutions.
Practice
x² = 9, so x = 3 or x = −3. (Or (x − 3)(x + 3) = 0.)
(x + 3)(x + 4) = 0, so x = −3 or x = −4.
x = (−4 ± √12)/2 = −2 ± √3, so x ≈ −0.27 or x ≈ −3.73.
Quick check
Which is a quadratic equation?
Factorise x² + 8x + 15.
Solve (x − 4)(x + 1) = 0.
- Quadratics have x² as the highest power and up to two solutions.
- To factorise: rearrange to = 0, factorise, set each bracket to zero.
- The quadratic formula x = (−b ± √(b² − 4ac)) / 2a solves any quadratic.
- The discriminant b² − 4ac tells you how many real solutions exist.